document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151193>Question 151193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 60. solve the equation algabraically log.4 x-log.4(x-1)=1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111082 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log.4 x-log.4(x-1)=1/2<BR>\n" );
document.write( "log.4(x/(x-1)) = 1/2<BR>\n" );
document.write( "log(x/(x-1))/log(4) = 1/2<BR>\n" );
document.write( "log(x/(x-1))/0.602 = 1/2<BR>\n" );
document.write( "log(x/(x-1)) = 0.301<BR>\n" );
document.write( "x/(x-1) = 10^(0.0301)<BR>\n" );
document.write( "x/(x-1) = 2<BR>\n" );
document.write( "x = 2x -2<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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document.write( "Try that out in the original equation, using base transformation<BR>\n" );
document.write( "log(2)/log(4)  - log(1)/log(4) = 1/2<BR>\n" );
document.write( " </SPAN>\n" );
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