document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151138>Question 151138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the slope of the line parallel to the line 4x-2y-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111064 by </B><A HREF=/tutors/aboutme.mpl?userid=galileo><B>galileo(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=galileo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope-intercept formula of a line is y = mx + b where m is the slope and b is                     <BR>\n" );
document.write( "                                                          the y-intercept<BR>\n" );
document.write( "4x-2y-1 = 0 \r<BR>\n" );
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document.write( "-2y = -4x + 1\r<BR>\n" );
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document.write( "  y = 2x - 1/2\r<BR>\n" );
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document.write( "  The slope of the line is 2 and a y-intercept of -1/2. Any line parallel to this line must also have a slope of 2. </SPAN>\n" );
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