document.write( "Question 151131: The baton twirler releases the baton into the air when it is 5 feet above the ground. The initial velocity of the baton is 30 feet per second. The twirler will catch the baton when it falls back to a height of 6 feet. How many seconds is the baton in the air? \n" ); document.write( "
Algebra.Com's Answer #111052 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The baton twirler releases the baton into the air when it is 5 feet above the ground. The initial velocity of the baton is 30 feet per second. The twirler will catch the baton when it falls back to a height of 6 feet. How many seconds is the baton in the air? \n" ); document.write( ": \n" ); document.write( "The equation for this, s(t)= height, t=time in seconds \n" ); document.write( ": \n" ); document.write( "s(t) = -16t^2 + 30t + 5 \n" ); document.write( ": \n" ); document.write( "Find the time that the baton is at 6 ft \n" ); document.write( ": \n" ); document.write( "-16t^2 + 30t + 5 = 6 \n" ); document.write( ": \n" ); document.write( "-16t^2 + 30t + 5 - 6 = 0 \n" ); document.write( ": \n" ); document.write( "-16t^2 + 30t - 1 = 0 \n" ); document.write( "; \n" ); document.write( "use the quadratic formula to solve this \n" ); document.write( " \n" ); document.write( "in this equation a=-16; b=30; c=-1 \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Two solutions: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t = +.034 sec (at 6' on the way up) \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t = +1.84 sec (at 6' on the way down) \n" ); document.write( " |