document.write( "Question 151131: The baton twirler releases the baton into the air when it is 5 feet above the ground. The initial velocity of the baton is 30 feet per second. The twirler will catch the baton when it falls back to a height of 6 feet. How many seconds is the baton in the air? \n" ); document.write( "
Algebra.Com's Answer #111043 by stanbon(75887)\"\" \"About 
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The baton twirler releases the baton into the air when it is 5 feet above the ground. The initial velocity of the baton is 30 feet per second. The twirler will catch the baton when it falls back to a height of 6 feet. How many seconds is the baton in the air?
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\n" ); document.write( "h(t) = -32t^2 + vot + so
\n" ); document.write( "6 = -32t^2 + 30t + 5
\n" ); document.write( "32t^2 - 30t + 1 = 0\r
\n" ); document.write( "\n" ); document.write( "t = [30 +- sqrt(30^2-4*32)]/64\r
\n" ); document.write( "\n" ); document.write( "t = [30 +- sqrt(772)]/64\r
\n" ); document.write( "\n" ); document.write( "t = [30 +- 27.785]/64\r
\n" ); document.write( "\n" ); document.write( "t = [0.0346 seconds (time the baton is at 6 ft. on the way up)
\n" ); document.write( " or t = 0.9029 seconds (time the baton is at 6 ft. on the way down)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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