document.write( "Question 151018: A RECTANGLE IS 4 TIMES AS LONG AS IT IS WIDE A SECOND RECTANGLE IS 5 CENTIMETERS LONGER AND 2 CENTIMETERS WIDER THAN THE FIRST. THE AREA OF THE SECOND RECTANGLE IS 270 SQUARE CENTIMETERS GREATER THAN THE FIRST. WHAT ARE THE DIMENSIONS OF THE ORIGINAL RECTANGLE \n" ); document.write( "
Algebra.Com's Answer #111006 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! We need to remember the following, \n" ); document.write( "1st rectangle (original) \n" ); document.write( " \n" ); document.write( "2nd rectangle, \n" ); document.write( " \n" ); document.write( "In \n" ); document.write( "So, \n" ); document.write( ". \n" ); document.write( "In \n" ); document.write( "Also, \n" ); document.write( "So, \n" ); document.write( "And we have to remember, \n" ); document.write( "Plug in eqn 1 in this condition: \n" ); document.write( "Therefore, equating A & C, \n" ); document.write( " \n" ); document.write( "Remember in \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We know \n" ); document.write( ". \n" ); document.write( "For checking & verification, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This satisfy condition B above -----> \n" ); document.write( "1870-1600=270cm \n" ); document.write( "Thank you, \n" ); document.write( "Jojo\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |