document.write( "Question 150990: suzy can run 4m/sec and tim can run 6m/sec. How far ahead of tim must suzy be to not to fall behind tim in the first 10 secondsof running? Use a graph to check ou answer? \n" ); document.write( "
Algebra.Com's Answer #110995 by ankor@dixie-net.com(22740)\"\" \"About 
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suzy can run 4m/sec and tim can run 6m/sec. How far ahead of tim must suzy be to not to fall behind tim in the first 10 seconds of running? Use a graph to check your answer?
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\n" ); document.write( "Let d = distance that T is ahead of S
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\n" ); document.write( "Write a distance equation: Dist = speed * 10 sec
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\n" ); document.write( "S's dist + head-start dist = T's dist
\n" ); document.write( "4(10) + d = 6(10)
\n" ); document.write( "40 + d = 60
\n" ); document.write( "d = 60 - 40
\n" ); document.write( "d = 20 m head start
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\n" ); document.write( "\"Use a graph to check your answer\"
\n" ); document.write( "let x = time running
\n" ); document.write( "let y = distance ran
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\n" ); document.write( "Suzy: y = 4x + 20; (green)
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\n" ); document.write( "Tim: y = 6x; (purple)
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\n" ); document.write( "y axis = dist, x axis = time
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-5%2C+15%2C+-10%2C+100%2C+6x%2C+4x%2B20%29+\"
\n" ); document.write( "You can see that T (purple) passes S (green) at 10 sec
\n" ); document.write( "And when x=0, S has a 20m headstart \n" ); document.write( "
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