document.write( "Question 151016: The average of 2 numbers is 15 and four times the difference between them is 4o. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #110941 by jojo14344(1513)\"\" \"About 
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Let \"x\"= 1st #, & \"y\"= 2nd #
\n" ); document.write( "1st condition: Average of 2 numbers is 15,
\n" ); document.write( "\"%28x%2By%29%2F2=15\"
\n" ); document.write( "2nd condition: 4 times the diff. is 40,
\n" ); document.write( "\"4%28x-y%29=40\"
\n" ); document.write( ".
\n" ); document.write( "In 1st condtn. we get \"x%2By=30\" --> REMEMBER THIS EQ'N,
\n" ); document.write( " \"x=30-y\" and substitute this \"x\" value in 2nd condtn.
\n" ); document.write( "\"4%2830-y-y%29=40\"
\n" ); document.write( "\"120-4y-4y=40\"
\n" ); document.write( "\"120-40=4y%2B4y\" ----> \"80=8y\"
\n" ); document.write( "\"y=10\", and REMEMBER EQ'N \"x%2B10=30\" ---> \"x=30-10\" --> \"x=20\"
\n" ); document.write( "To check,
\n" ); document.write( "Go back 1st condtn.; \"%2820%2B10%29%2F2=15\" ----> \"15=15\"
\n" ); document.write( "For 2nd condtn.; \"4%2820-10%29=40\" ------> \"40=40\"
\n" ); document.write( "Thank you
\n" ); document.write( "Jojo
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