document.write( "Question 150954: Use a system of equations to solve the word problem. The perimeter of a rectangle is 56 inches, and its area is 192 square inches. What are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #110926 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2x+2y=56 \n" ); document.write( "xy=192 \n" ); document.write( "x=192/y \n" ); document.write( "2(192/y)+2y=56 \n" ); document.write( "384/y+2y=56 \n" ); document.write( "(384+2y^2)/y=56 \n" ); document.write( "2y^2+384=56y \n" ); document.write( "2y^2-56y+384=0 \n" ); document.write( "2(y^2-28y+192)=0 \n" ); document.write( "2(y-16)(y-12)=0 \n" ); document.write( "y-16=0 \n" ); document.write( "y=16 answer. \n" ); document.write( "2x+2*16=56 \n" ); document.write( "2x+32=56 \n" ); document.write( "2x=56-32 \n" ); document.write( "2x=24 \n" ); document.write( "x=24/2 \n" ); document.write( "x=12 answer. \n" ); document.write( "poof: \n" ); document.write( "12*16=192 \n" ); document.write( "192=192\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |