document.write( "Question 150982: This is a summer assignment. I don't have a book.\r
\n" ); document.write( "\n" ); document.write( "Solve the equation \"+x%5E2+-+5x+%2B+2+=+0+\"
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Algebra.Com's Answer #110916 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x%2B2=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=1\", \"b=-5\", and \"c=2\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%281%29%282%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=-5\", and \"c=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%281%29%282%29+%29%29%2F%282%281%29%29\" Negate \"-5\" to get \"5\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-4%281%29%282%29+%29%29%2F%282%281%29%29\" Square \"-5\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-8+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%282%29\" to get \"8\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+17+%29%29%2F%282%281%29%29\" Subtract \"8\" from \"25\" to get \"17\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+17+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285%2Bsqrt%2817%29%29%2F%282%29\" or \"x+=+%285-sqrt%2817%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So our answers are \"x+=+%285%2Bsqrt%2817%29%29%2F%282%29\" or \"x+=+%285-sqrt%2817%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=4.562\" or \"x=0.438\"
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