document.write( "Question 150981: x^2 – 2x + 1
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Algebra.Com's Answer #110913 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"%28x%5E2-2x%2B1%29%2F%28x-1%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28x-1%29%28x-1%29%29%2F%28x-1%29\" Factor \"x%5E2-2x%2B1\" to get \"%28x-1%29%28x-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28%28x-1%29%29%28x-1%29%29%2F%28highlight%28%28x-1%29%29%29\" Highlight the common terms. \r
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\n" ); document.write( "\n" ); document.write( "\"%28cross%28%28x-1%29%29%28x-1%29%29%2F%28cross%28%28x-1%29%29%29\" Cancel out the common terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x-1\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So \"%28x%5E2-2x%2B1%29%2F%28x-1%29\" simplifies to \"x-1\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28x%5E2-2x%2B1%29%2F%28x-1%29=x-1\" where \"x%3C%3E1\"
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