document.write( "Question 150934: A rectangle's width is six times its length. The perimeter of the rectangle is two hundred thirty-eight feet. What is the area of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #110880 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Area = L*W \n" ); document.write( "W = 6L \n" ); document.write( "Perimeter = 2L + 2W = 238 \n" ); document.write( "P = 2L + 2(6L) \n" ); document.write( "P = 14L \n" ); document.write( "238 = 14L \n" ); document.write( "17=L \n" ); document.write( "W = 6L = 102\r \n" ); document.write( "\n" ); document.write( "A=WL = 102*17 = 1734 \n" ); document.write( " |