document.write( "Question 150915: A cylindrical container has a base area of 100 cm^2 and is 12 cm high. If the container is one-third filled with water, what is the volume of the water in the container? \n" ); document.write( "
Algebra.Com's Answer #110878 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
We know the in finding the \"Volume\" of the container = \"pi%28r%5E2%29h\"
\n" ); document.write( "The \"height\" is given which is \"%281%2F3%29%2812cm%29\", but we don't have the radius, \"r\".
\n" ); document.write( "Since \"Area\" is given, we can get it there, with the formula,
\n" ); document.write( "\"A=2pi%28r%5E2%29%2B2pi%28r%29h\"---- area on the top and base + area on the sides
\n" ); document.write( "\"100=2pi%28r%5E2%2B%28rh%29%29\"
\n" ); document.write( "\"%28100%2F2pi%29=r%5E2%2Brh\"
\n" ); document.write( "Substituting & re-arranging,
\n" ); document.write( "\"r%5E2%2B12r-%2850%2Fpi%29=0\"
\n" ); document.write( "by Quadratic eqn, \"x=r\", \"a=1\", \"b=12\",\"c=+-50%2Fpi\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( "\"x=%28-12%2B-sqrt%2812%5E2-4%2A1%2A-50%2Fpi%29%29%2F%282%2A1%29\"
\n" ); document.write( "\"x=%28-12%2B-sqrt%28144%2B200%2Fpi%29%29%2F2\"
\n" ); document.write( "\"x=%28-12%2B-sqrt%28207.66198%29%29%2F2\"
\n" ); document.write( "\"x=%28-12%2B-14.41%29%2F2\"
\n" ); document.write( "\"x=%28-12%2B14.41%29%2F2\"-----> \"x=1.205\"
\n" ); document.write( "\"x=%28-12-14.41%29%2F2\"-----> \"x=-13.205\"
\n" ); document.write( "USE \"x=1.205=r\"
\n" ); document.write( "So \"V=pi%281.205%5E2%29%2812%2F3%29\"
\n" ); document.write( "\"V=5.81%28pi%29\"cc
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( "
\n" );