document.write( "Question 150932: How do you factor by grouping, 48x^2y + 20xz +12xy + 5z, whats the answer? \n" ); document.write( "
Algebra.Com's Answer #110877 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"48x%5E2y%2B20xz%2B12xy%2B5z\" Start with the given expression\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%2848x%5E2y%2B20xz%29%2B%2812xy%2B5z%29\" Group the terms into two groups\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x%2812xy%2B5z%29%2B1%2812xy%2B5z%29\" Factor out the GCF \"4x\" out of the first group. Factor out the GCF \"1\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%284x%2B1%29%2812xy%2B5z%29\" Since we have the common term \"12xy%2B5z\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"48x%5E2y%2B20xz%2B12xy%2B5z\" factors to \"%284x%2B1%29%2812xy%2B5z%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );