document.write( "Question 22678: The sum of three numbers is 301. The second number is 3 less than twelve times
\n" ); document.write( "the first number. The third number is 4 more than seven times the first number.
\n" ); document.write( "Find the three numbers. \n" ); document.write( "

Algebra.Com's Answer #11087 by Paul(988) $\"\"$ $\"About$

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First number = x
\n" ); document.write( "Second number = y
\n" ); document.write( "Third number = z\r
\n" ); document.write( "\n" ); document.write( "x+y+x=301
\n" ); document.write( "y=12x-3----------------->12x-y=3
\n" ); document.write( "z=4+7x------------------>7x-z=-4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x+y+z=301
\n" ); document.write( "7x-z=-4
\n" ); document.write( "8x+y=297 <--------New equation\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "8x+y=297
\n" ); document.write( "12x-y=3
\n" ); document.write( "20x=300
\n" ); document.write( " $\"20x%2F20=300%2F20\"$
\n" ); document.write( "x=15\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "y=12(15)-3
\n" ); document.write( "y=177
\n" ); document.write( "z=4+7(15)
\n" ); document.write( "z=109
\n" ); document.write( "Hence, the three numbers are 15, 109 and 177. \n" ); document.write( "

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