document.write( "Question 150914: If the diameter of a sphere is doubled, its surface becomes
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document.write( "A. doubled the orginal surface
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document.write( "B.four times the orginal surface
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document.write( "C.eight times the orginal surface
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document.write( "D. three times the orginal surface
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Algebra.Com's Answer #110848 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! Surface area of a sphere: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember, the diameter is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the old equation is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The ratio of the new surface area to the old surface area is then:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the new surface area is simply 4 times the original surface area. So the answer is B \n" ); document.write( " |