document.write( "Question 150589: the altitude of an isosceles trapezoid is 20cm. if the lower base is 10cm longer than the upper base the area of the trapezoid is 220sq. cm, find the lengths of the bases. \n" ); document.write( "
Algebra.Com's Answer #110835 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! Area of a trapezoid is similar to a triangle, the only difference it has 2 bases. If a triangle is \n" ); document.write( ". \n" ); document.write( "In the problem, let \"a\"=upper base=\"x\", \"b\"=lower base=\"x+10cm\", and \n" ); document.write( "altitude=h=20cm \n" ); document.write( "Substituting in our eqn with given, A=220 sqcm}, \n" ); document.write( "220 =(1/2)(20)(x+x+10) = (1/2)(20)(2x+10) \n" ); document.write( "cross multiply, \n" ); document.write( "440=40x+200 \n" ); document.write( "440-200=40x \n" ); document.write( "240=40x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "In doubt? to go back to our eqn and you'll see, A=(1/2)(h)(a+b) \n" ); document.write( "thank you, \n" ); document.write( "Jojo \n" ); document.write( " |