document.write( "Question 150901: tan 11pi/6 \n" ); document.write( "
Algebra.Com's Answer #110834 by jim_thompson5910(35256)\"\" \"About 
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Take note that \"pi%2F6%2B5pi%2F3=11pi%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "So \r
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\n" ); document.write( "\n" ); document.write( "\"tan%2811pi%2F6%29=tan%28pi%2F6%2B5pi%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( " Use the Sum-Difference identity to rewrite the right side.\r
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\n" ); document.write( "\n" ); document.write( " Using the unit circle, we get \"tan%28pi%2F6%29=sqrt%283%29%2F3\" and \"tan%285pi%2F3%29=-sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan%2811pi%2F6%29=%28%28sqrt%283%29%2F3%29-sqrt%283%29%29%2F%281-%28-1%29%29\" Multiply \"sqrt%283%29%2F3\" and \"-sqrt%283%29\" to get \"%28sqrt%283%29%2F3%29%28-sqrt%283%29%29=-%28sqrt%283%29sqrt%283%29%29%2F3=-3%2F3=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan%2811pi%2F6%29=%28%28sqrt%283%29%2F3%29-sqrt%283%29%29%2F%282%29\" Combine like terms in the denominator.\r
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\n" ); document.write( "\n" ); document.write( "\"tan%2811pi%2F6%29=%28%28sqrt%283%29%2F3%29-3sqrt%283%29%2F3%29%2F%282%29\" Multiply \"-sqrt%283%29\" by \"3%2F3\" \r
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\n" ); document.write( "\n" ); document.write( "\"tan%2811pi%2F6%29=%28-2sqrt%283%29%2F3%29%2F%282%29\" Combine the fractions in the numerator.\r
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\n" ); document.write( "\n" ); document.write( "\"tan%2811pi%2F6%29=-sqrt%283%29%2F3\" Divide and simplify.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"tan%2811pi%2F6%29=-sqrt%283%29%2F3\"
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