document.write( "Question 150897: what is the equation of a line with a slope of -2/3 and y- intercept of 17 \n" ); document.write( "
Algebra.Com's Answer #110827 by jim_thompson5910(35256)\"\" \"About 
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If an equation has a y-intercept of 17, this means that the equation goes through the point (0,17)\r
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"-2%2F3\" which goes through the point (0,17), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-17=%28-2%2F3%29%28x-0%29\" Plug in \"m=-2%2F3\", \"x%5B1%5D=0\", and \"y%5B1%5D=17\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-17=%28-2%2F3%29x%2B%28-2%2F3%29%28-0%29\" Distribute \"-2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-17=%28-2%2F3%29x%2B0\" Multiply \"-2%2F3\" and \"-0\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B0%2B17\" Add 17 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B17\" Combine like terms \"0\" and \"17\" to get \"17\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"-2%2F3\" which goes through the point (0,17) is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-2%2F3%29x%2B17\" which is now in \"y=mx%2Bb\" form where the slope is \"m=-2%2F3\" and the y-intercept is \"b=17\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-2%2F3%29x%2B17\" and plot the point (0,17), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-2%2F3%29x%2B17\" through the point (0,17)\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"-2%2F3\" and goes through the point (0,17), this verifies our answer.
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