document.write( "Question 150851: Sulfuric acid (H2SO4) can be used to remove water from organic materials leaving behind a residue of black carbon. If beaker A contains a 15% solution of sulfuric acid and beaker B contains a 20% solution of sulfuric acid, how much from each beaker should be used to make 6 liters of a 18% solution of sulfuric acid?
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Algebra.Com's Answer #110808 by josmiceli(19441)\"\" \"About 
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In words:
\n" ); document.write( "(liters of acid in beaker A) + (liters of acid in beaker B) / (total liters of solution in A and B) = % solution of acid
\n" ); document.write( "Let A = liters of solution needed from beaker A
\n" ); document.write( "Let B = liters of solution needed from beaker B
\n" ); document.write( "\"%28.15A+%2B+.2B%29+%2F+%28A+%2B+B%29+=+.18\"
\n" ); document.write( "Note that we are told \"A+%2B+B+=+6\"liters
\n" ); document.write( "\"%28.15A+%2B+.2B%29+%2F+6+=+.18\"
\n" ); document.write( "Multiply both sides by \"6\"
\n" ); document.write( "\".15A+%2B+.2B+=+1.08\"
\n" ); document.write( "And since \"A+%2B+B+=+6\"
\n" ); document.write( "\"B+=+6+-+A\"
\n" ); document.write( "\".15A+%2B+.2%2A%286+-+A%29+=+1.08\"
\n" ); document.write( "\".15A+%2B+1.2+-+.2A+=+1.08\"
\n" ); document.write( "\"-.05A+=+-.12\"
\n" ); document.write( "\"A+=+2.4\"liters
\n" ); document.write( "Given is \"A+%2B+B+=+6\"
\n" ); document.write( "\"B+=+6+-+2.4\"
\n" ); document.write( "\"B+=+3.6\"
\n" ); document.write( "2.4 liters of solution are needed from beaker A
\n" ); document.write( "and 3.6 liters of solution are needed from beaker B
\n" ); document.write( "check answer:
\n" ); document.write( "\"%28.15A+%2B+.2B%29+%2F+6+=+.18\"
\n" ); document.write( "\"%28.15%2A2.4+%2B+.2%2A3.6%29+%2F+6+=+.18\"
\n" ); document.write( "\"%28.36+%2B+.72%29+%2F+6+=+.18\"
\n" ); document.write( "\"1.08+%2F+6+=+.18\"
\n" ); document.write( "\"1.08+=+.18%2A6\"
\n" ); document.write( "\"1.08+=+1.08\"
\n" ); document.write( "OK
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