document.write( "Question 150851: Sulfuric acid (H2SO4) can be used to remove water from organic materials leaving behind a residue of black carbon. If beaker A contains a 15% solution of sulfuric acid and beaker B contains a 20% solution of sulfuric acid, how much from each beaker should be used to make 6 liters of a 18% solution of sulfuric acid?
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Algebra.Com's Answer #110807 by Fombitz(32388)\"\" \"About 
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Let's call the amount from beaker A, A.
\n" ); document.write( "Let's call the amount from beaker B, B.
\n" ); document.write( "The total final volume is 6 liters.
\n" ); document.write( "1.\"A%2BB=6\"
\n" ); document.write( "The final concentration is 18%.
\n" ); document.write( "2.\"A%280.15%29%2BB%280.20%29=%28A%2BB%29%280.18%29\"
\n" ); document.write( "Let's multiply equation 2 by 100 to get rid of decimals.
\n" ); document.write( "2.\"15A%2B20B=18%28A%2BB%29\"
\n" ); document.write( "2.\"15A%2B20B=18A%2B18B%29\"
\n" ); document.write( "2.\"3A-2B=0\"
\n" ); document.write( "We can use eq. 2 to solve for B in terms of A.
\n" ); document.write( "2.\"3A-2B=0\"
\n" ); document.write( "\"2B=3A\"
\n" ); document.write( "\"B=%283%2F2%29A\"
\n" ); document.write( "Now substitute this into eq. 1 and solve for A.
\n" ); document.write( "1.\"A%2BB=6\"
\n" ); document.write( "\"A%2B%283%2F2%29A=6\"
\n" ); document.write( "\"%285%2F2%29A=6\"
\n" ); document.write( "\"A=12%2F5\"
\n" ); document.write( "Now back substitute to find B,
\n" ); document.write( "\"B=%283%2F2%29A\"
\n" ); document.write( "\"B=%283%2F2%29%2812%2F5%29\"
\n" ); document.write( "\"B=18%2F5\"
\n" ); document.write( "2.4 liters of solution A and 3.6 liters of solution B.
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