document.write( "Question 150850: Solve This Problem Interactively Customize This Problem
\n" ); document.write( "A mixture containing 6% salt is to be mixed with 2 ounces of a mixture which is 15% salt, in order to obtain a solution which is 12% salt. How much of the first solution must be used?
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Algebra.Com's Answer #110806 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A mixture containing 6% salt is to be mixed with 2 ounces of a mixture which is 15% salt, in order to obtain a solution which is 12% salt. How much of the first solution must be used?
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\n" ); document.write( "How do you solve a problem \"Interactively\"?
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\n" ); document.write( "Anyway.
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\n" ); document.write( "Let x = amt of 1st solution required
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\n" ); document.write( ".06x + .15(2) = .12(x+2)
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\n" ); document.write( ".06x + .3 = .12x + .24
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\n" ); document.write( ".3 - .24 = .12x - .06x
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\n" ); document.write( ".06 = .06x
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\n" ); document.write( "x = 1 oz of the 1st solution required
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\n" ); document.write( "Check solution:
\n" ); document.write( ".06(1) + .15(2) = .12(1+2)
\n" ); document.write( ".06 + .30 = .36 \n" ); document.write( "

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