document.write( "Question 150883This question is from textbook intermediate algebra
\n" ); document.write( ": I don't know if you have that textbook, but if so you may be able to help me. in section 8.1 example 4 and 8 there are examples where the number suddenly changes into i. i ll write it down in case you don/t have the book.\r
\n" ); document.write( "\n" ); document.write( "the example 4:\r
\n" ); document.write( "\n" ); document.write( "(2x-5)2 = -16
\n" ); document.write( "2x-5 = +- square root -16
\n" ); document.write( "2x-5 = +- 4i
\n" ); document.write( "2x=5+-4i
\n" ); document.write( "x=5+-4i / 2\r
\n" ); document.write( "\n" ); document.write( "i have had the section about i in college but i don't understand the transition from root -16 to 4i. how does the i come into play?\r
\n" ); document.write( "\n" ); document.write( "8.1 example 8 is also sth with i, if you have the book it would be great if you could explain that to me as well.\r
\n" ); document.write( "\n" ); document.write( "anna
\n" ); document.write( "

Algebra.Com's Answer #110803 by mangopeeler07(462)\"\" \"About 
You can put this solution on YOUR website!
Dear Anna,\r
\n" ); document.write( "\n" ); document.write( "i is an imaginary number. you attain the square root of any negative number by taking the square root of the opposite and multiplying it by + or - i. So the square root of -16 is the square root of 16 (4 or -4) multiplied by i (4i or -4i). Since i^2=-1, +4i or -4i would be the sqaure root of -16, because:\r
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\n" ); document.write( "\n" ); document.write( "4i(4i)=(4)^2(i^2)
\n" ); document.write( "(4)^2(i^2)=16(-1)
\n" ); document.write( "16(-1)=-16\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-4i(-4i)=(-4)^2(i^2)
\n" ); document.write( "(-4)^2(i^2)=16(-1)
\n" ); document.write( "16(-1)=-16\r
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\n" ); document.write( "\n" ); document.write( "I hope that this has helped you.
\n" ); document.write( "Sincerely,
\n" ); document.write( "Alani (mangopeeler07)
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