document.write( "Question 150880: Fractor each of the following; x^2+x-6 and 3x^2+11x+10 ,I know how to fractor things like x^2+8x+4 but I dont really understand how to fractor x^2+x-6 or 3x^2+11x+10, could someone please explain it to me? \n" ); document.write( "
Algebra.Com's Answer #110801 by mangopeeler07(462)\"\" \"About 
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1. x^2+x-6
\n" ); document.write( "Since this has a + and a -, then you set it up like this:
\n" ); document.write( "(x+)(x-)
\n" ); document.write( "Factors of 6 whose difference is 1: 3 and 2
\n" ); document.write( "The higher number (3) will go in the (x+), since the x term is positive.
\n" ); document.write( "(x+3)(x-2)\r
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\n" ); document.write( "\n" ); document.write( "2.3x^2+11x+10
\n" ); document.write( "Since this has two +'s, you set it up like this:
\n" ); document.write( "(3x+)(x+)
\n" ); document.write( "Since 3 is prime, it has to be 3x and x. Then the other two numbers must be so that one number times 3x + the other number times x equals 11x.\r
\n" ); document.write( "\n" ); document.write( "Those number would be 2 and 5, but how do you put them into (3x+)(x+)?
\n" ); document.write( "(3x+2)(x+5) foils out to 3x^2+17x+10, so it's not that way. so it's:
\n" ); document.write( "(3x+5)(x+2)\r
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