document.write( "Question 150832: The lenght and width of a rectangle are in the ratio 3:2. If the length is increased by 20 and teh width is decreased by 5, the ratio of the length to the width becomes 2:1. Find teh length and width of this rectangle. \n" ); document.write( "
Algebra.Com's Answer #110760 by mangopeeler07(462)\"\" \"About 
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L/w=3/2\r
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\n" ); document.write( "\n" ); document.write( "Cross multiply
\n" ); document.write( "3w=2L
\n" ); document.write( "Divide by 3
\n" ); document.write( "w=2L/3\r
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\n" ); document.write( "\n" ); document.write( "L+20/w-5=2/1
\n" ); document.write( "Cross multiply
\n" ); document.write( "2w-10=L+20\r
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\n" ); document.write( "\n" ); document.write( "Plug in w
\n" ); document.write( "2(2L/3)-10=L+20\r
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\n" ); document.write( "\n" ); document.write( "Distribute
\n" ); document.write( "4L/3-10=L+20\r
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\n" ); document.write( "\n" ); document.write( "Subtract 4/3L from both sides
\n" ); document.write( "-10=-1/3L+20\r
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\n" ); document.write( "\n" ); document.write( "Subtract 20 from both sides
\n" ); document.write( "-30=-1/3L\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by -3
\n" ); document.write( "90=L\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "90/w=3/2
\n" ); document.write( "Cross multiply
\n" ); document.write( "180=3w
\n" ); document.write( "60=w\r
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\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "Length=90
\n" ); document.write( "Width=60\r
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