document.write( "Question 150815: If the length of a rectangular field is 8 feet more than double of its width. Find the dimensions of the field if its area is 540 square feet?\r
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Algebra.Com's Answer #110759 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! If the length of a rectangular field is 8 feet more than double of its width. Find the dimensions of the field if its area is 540 square feet? \n" ); document.write( ". \n" ); document.write( "Let w = width of field \n" ); document.write( "2w+8 = length of field \n" ); document.write( ". \n" ); document.write( "w(2w+8)= 540 \n" ); document.write( "2w^2+8w= 540 \n" ); document.write( "2w^2+8w-540 = 0 \n" ); document.write( "w^2+4w-270 = 0 \n" ); document.write( ". \n" ); document.write( "Since you can't factor you must use the quadratic equation. Doing so yields: \n" ); document.write( "w={14.55, -18.55} \n" ); document.write( ". \n" ); document.write( "Only the positive answer would be correct. Therefore: \n" ); document.write( "w = 14.55 feet (width) \n" ); document.write( "2w+8 = 37.1 feet (length) \n" ); document.write( ". \n" ); document.write( "Below is the quadratic solution: \n" ); document.write( "
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