document.write( "Question 150830: the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #110757 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2w+2L=66 \n" ); document.write( "2(2w)+2(L+22)=136\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for 2w in the first equation \n" ); document.write( "2w=66-2L\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug that into the second equation \n" ); document.write( "2(66-2L)+2(L+22)=136\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute \n" ); document.write( "132-4L+2L+44=136\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms \n" ); document.write( "176-2L=136\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 176 from both sides \n" ); document.write( "-2L=-40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by -2 \n" ); document.write( "L=20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2w=66-2L \n" ); document.write( "2w=66-2(20) \n" ); document.write( "2w=66-40 \n" ); document.write( "2w=26 \n" ); document.write( "w=13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "Length=20m \n" ); document.write( "Width=13m \n" ); document.write( " |