document.write( "Question 150830: the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #110757 by mangopeeler07(462)\"\" \"About 
You can put this solution on YOUR website!
the perimeter of a rectangle is 66m if the width were double and the length were increased by 22m, the perimeter would be 136 what is the length and width of the rectangle\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2w+2L=66
\n" ); document.write( "2(2w)+2(L+22)=136\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for 2w in the first equation
\n" ); document.write( "2w=66-2L\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug that into the second equation
\n" ); document.write( "2(66-2L)+2(L+22)=136\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Distribute
\n" ); document.write( "132-4L+2L+44=136\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Combine like terms
\n" ); document.write( "176-2L=136\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract 176 from both sides
\n" ); document.write( "-2L=-40\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide both sides by -2
\n" ); document.write( "L=20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2w=66-2L
\n" ); document.write( "2w=66-2(20)
\n" ); document.write( "2w=66-40
\n" ); document.write( "2w=26
\n" ); document.write( "w=13\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "Length=20m
\n" ); document.write( "Width=13m
\n" ); document.write( "
\n" );