document.write( "Question 150822: A tank can be filled by two pipes separately in 10 and 15 minutes respectively. When a third pipe is used simultaneously with the first two pipes, the tank can be filled in 4 minutes. How long would it take the third pipe alone to fill the tank? \n" ); document.write( "
Algebra.Com's Answer #110752 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A tank can be filled by two pipes separately in 10 and 15 minutes respectively. When a third pipe is used simultaneously with the first two pipes, the tank can be filled in 4 minutes. How long would it take the third pipe alone to fill the tank? \n" ); document.write( ": \n" ); document.write( "Let x = time (in min) required by the 3rd pipe alone: \n" ); document.write( "Let the full tank = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 30x to eliminate the denominators, results \n" ); document.write( "3x(4) + 2x(4) + 30(4) = 30x \n" ); document.write( ": \n" ); document.write( "12x + 8x + 120 = 30x \n" ); document.write( ": \n" ); document.write( "20x + 120 = 30x \n" ); document.write( ": \n" ); document.write( "120 = 30x - 20x \n" ); document.write( ": \n" ); document.write( "120 = 10x \n" ); document.write( "x = \n" ); document.write( "x = 12 min for the third pipe to fill it alone \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution using a calc \n" ); document.write( "(4/10) + (4/15) + (4/12) = \n" ); document.write( " .4 + .267 + .333 = 1 \n" ); document.write( " \n" ); document.write( " |