document.write( "Question 150813: I'm confused with this function problem.\r
\n" ); document.write( "\n" ); document.write( "It states: For the function f(x) = x^2-2x+1 solve f(x) = 0.\r
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Algebra.Com's Answer #110736 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+x%5E2-2x%2B1+\" Start with the given function\r
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\n" ); document.write( "\n" ); document.write( "\"0=+x%5E2-2x%2B1+\" Plug in \"f%28x%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Here are two ways to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Method # 1 Factoring:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%28x-1%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x-1=0\" or \"x-1=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=1\" or \"x=1\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "Since we have a repeating answer, our only answer is \"x=1\"\r
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\n" ); document.write( "\n" ); document.write( "Method # 2 Quadratic Formula:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "From \"x%5E2-2x%2B1\", we can see that \"a=1\", \"b=-2\", and \"c=1\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%281%29+%29%29%2F%282%281%29%29\" Plug in \"a=1\", \"b=-2\", and \"c=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%281%29+%29%29%2F%282%281%29%29\" Negate \"-2\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4-4%281%29%281%29+%29%29%2F%282%281%29%29\" Square \"-2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+4-4+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%281%29\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+0+%29%29%2F%282%281%29%29\" Subtract \"4\" from \"4\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+sqrt%28+0+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B-+0%29%2F%282%29\" Take the square root of \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282+%2B+0%29%2F%282%29\" or \"x+=+%282+-+0%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%282%29%2F%282%29\" or \"x+=++%282%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+1\" or \"x+=+1\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x+=+1\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "Using either method, we get the solution \"x+=+1\"\r
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