document.write( "Question 150800: Solve the system of linear equations by the substitution method.\r
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document.write( "y = -4/3x\r
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document.write( "4x + 2y = 3/4 \n" );
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Algebra.Com's Answer #110720 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! y = -4/3x\r \n" ); document.write( "\n" ); document.write( "4x + 2y = 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in -4/3x for y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x + 2(-4/3x)= 3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute \n" ); document.write( "*(4)x-(8/3)x=3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "*(4=12/3, so (4)x= (12/3)x.........(12/3)x-(8/3)x=4/3x)\r \n" ); document.write( "\n" ); document.write( "4/3x=3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "*Divide both sides by 4/3 to isolate x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4/3x divided by 4/3= 3/4 divided by 4/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=9/16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=9/16 \n" ); document.write( "y=-4/3x \n" ); document.write( "y=-4/3(9/16) \n" ); document.write( "y=-3/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "x=9/16 \n" ); document.write( "y=-3/4 \n" ); document.write( " |