document.write( "Question 150688: Mrs Tan bought a DVD player and a HI-FI set at a discount of 20%. She paid a total of $2800. If the price of the DVD player is 40% that of the HI-FI set, what was the price of the DVD player before the discount? \n" ); document.write( "
Algebra.Com's Answer #110650 by nerdybill(7384)\"\" \"About 
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Mrs Tan bought a DVD player and a HI-FI set at a discount of 20%. She paid a total of $2800. If the price of the DVD player is 40% that of the HI-FI set, what was the price of the DVD player before the discount?
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\n" ); document.write( "Let x = cost of hi-fi set
\n" ); document.write( "then
\n" ); document.write( ".40x = cost of dvd player
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\n" ); document.write( "we derive oure equation from: \"Mrs Tan bought a DVD player and a HI-FI set at a discount of 20%. She paid a total of $2800.\"
\n" ); document.write( ".80(x + .40x) = 2800
\n" ); document.write( "(x + .40x) = 3500
\n" ); document.write( "x(1+.40) = 3500
\n" ); document.write( "x(1.40) = 3500
\n" ); document.write( "x = 3500/1.40
\n" ); document.write( "x = $2500(cost of hi-fi set)
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\n" ); document.write( ".40x = .40(2500) = $1000 (cost of dvd)
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