document.write( "Question 150683: A man invests $10,000.00 in two enterprises. One enterprise yields 8% per year and the other yields 10% per year. If the income from both investments is $940.00 annually, how much did he invest in each enterprise? \n" ); document.write( "

Algebra.Com's Answer #110621 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"a\"$ = the 8% per yr investment
\n" ); document.write( "Let $\"b\"$ = the 10% per year investment
\n" ); document.write( " $\".08a+%2B+.1b+=+940\"$
\n" ); document.write( " $\"a+%2B+b+=+10000\"$
\n" ); document.write( " $\"b+=+10000+-+a\"$
\n" ); document.write( " $\".08a+%2B+.1%2A%2810000+-+a%29+=+940\"$
\n" ); document.write( " $\".08a+%2B+1000+-+.1a+=+940\"$
\n" ); document.write( " $\"-.02a+=+-60\"$
\n" ); document.write( " $\"a+=+60%2F.02\"$
\n" ); document.write( " $\"a+=+3000\"$
\n" ); document.write( "And, since
\n" ); document.write( " $\"a+%2B+b+=+10000\"$ ,
\n" ); document.write( " $\"3000+%2B+b+=+10000\"$
\n" ); document.write( " $\"b+=+7000\"$
\n" ); document.write( "He invested $3,000 in the 8% investment
\n" ); document.write( "He invested $7,000 in the 10% investment
\n" ); document.write( "check:
\n" ); document.write( " $\".08a+%2B+.1b+=+940\"$
\n" ); document.write( " $\".08%2A3000+%2B+.1%2A7000+=+940\"$
\n" ); document.write( " $\"240+%2B+700+=+940\"$
\n" ); document.write( " $\"940+=+940\"$
\n" ); document.write( "OK \n" ); document.write( "

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