document.write( "Question 150681This question is from textbook elementary and intermediate algebra
\n" ); document.write( ": how do you find the dimensions of the length and the width of a rectangle that is 2ft longer than its width if the ratio of the length to the width was 8 to 5? \n" ); document.write( "

Algebra.Com's Answer #110620 by josmiceli(19441) $\"\"$ $\"About$

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Call the length $\"l\"$
\n" ); document.write( "Call the width $\"w\"$
\n" ); document.write( " $\"l%2Fw+=+8%2F5\"$
\n" ); document.write( " $\"l+=+w+%2B+2\"$
\n" ); document.write( " $\"%28w+%2B+2%29%2Fw+=+8%2F5\"$
\n" ); document.write( "Multiply both sides by $\"5w\"$
\n" ); document.write( " $\"5%2A%28w+%2B+2%29+=+8w\"$
\n" ); document.write( " $\"5w+%2B+10+=+8w\"$
\n" ); document.write( " $\"3w+=+10\"$
\n" ); document.write( " $\"w+=+10%2F3\"$
\n" ); document.write( " $\"l+=+10%2F3+%2B+2\"$
\n" ); document.write( " $\"l+=+10%2F3+%2B+6%2F3\"$
\n" ); document.write( " $\"l+=+16%2F3\"$
\n" ); document.write( "The length is $\"%2816%2F3%29%2A12+=+64\"$ in.
\n" ); document.write( "The width is $\"%2810%2F3%29%2A12+=+40\"$ in.
\n" ); document.write( "check answer:
\n" ); document.write( "The length is $\"24\"$ in longer than the width
\n" ); document.write( " $\"l%2Fw+=+8%2F5\"$
\n" ); document.write( " $\"64%2F40+=+8%2F5\"$
\n" ); document.write( " $\"5%2A64+=+8%2A40\"$
\n" ); document.write( " $\"320+=+320\"$
\n" ); document.write( "OK
\n" ); document.write( " $\"l+=+40+%2B+24\"$
\n" ); document.write( " $\"l+=+64\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );