document.write( "Question 22662: Convert to logarithm form:\r
\n" ); document.write( "\n" ); document.write( "32^2/5=4 \n" ); document.write( "
Algebra.Com's Answer #11062 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
What base of log do you want? Lets do it to base 10...i shall just write it as \"log\"...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(2/5)log32 = log4
\n" ); document.write( "2log32 = 5log4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Where do you want to take it?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To me, the 32 and 4 both SHOUT 2 at me..2^5 is 32 and 2^2 is 4, so we have:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282%5E5%29%5E%282%2F5%29+=+2%5E2\" which then becomes \"2%5E2+=+2%5E2\", which shows that the lefthand side is actually the SAME values as 4...no need to take logs\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "jon.
\n" ); document.write( " \n" ); document.write( "
\n" );