document.write( "Question 150668:  In 1995 the life expectancy of a male in a certain country was 62.6 years In 2001 it was 64.9 years Let E represent the life expectancy in year t and let t represent the number of years since 1995\r
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document.write( "The linear function E(t) that fits the data is\r
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document.write( "E(t)= t + 
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document.write( "(round to the nearest tenth)\r
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document.write( "Use the function to predict the life expectancy of males in 2005
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document.write( "E(14)=
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document.write( "(round to the nearest tenth)
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| Algebra.Com's Answer #110598 by stanbon(75887)      You can put this solution on YOUR website! In 1995 the life expectancy of a male in a certain country was 62.6 years In 2001 it was 64.9 years Let E represent the life expectancy in year t and let t represent the number of years since 1995 \n" ); document.write( "---------- \n" ); document.write( "You have two points: (0,62.6) and (6,64.9), where x is the number of years after \n" ); document.write( "1995. \n" ); document.write( "------------------------------- \n" ); document.write( "slope: (64.9-62.6)/(6-0) = 2.3/6 = 23/60 \n" ); document.write( "------------- \n" ); document.write( "intercept: when x = 0, y = 62.6 \n" ); document.write( "----------------------------- \n" ); document.write( "Equation: \n" ); document.write( " E(t) = (23/60)t + 62.6 \n" ); document.write( "--------------------------- \n" ); document.write( "The linear function E(t) that fits the data is \n" ); document.write( "(round to the nearest tenth) \n" ); document.write( "Use the function to predict the life expectancy of males in 2005 \n" ); document.write( "E(14)= (23/60)*14 + 62.6 \n" ); document.write( "E(14) = 68.0 \n" ); document.write( "(round to the nearest tenth) \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |