document.write( "Question 150655: determine the perimeter of a square with diagonal of 72 squared centimeters? \n" ); document.write( "

Algebra.Com's Answer #110591 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
The diagonal cuts the square into two right triangles with 45 degree. The hypotenuse is 72 ( I assume you meant 72 centimeters, not 72 squared centimeters).\r
\n" ); document.write( "\n" ); document.write( "If the hypotenuse is 72, then the sides are $\"72%2Fsqrt%282%29\"$ = $\"36%2Asqrt%282%29\"$
\n" ); document.write( "A square with side of $\"36%2Asqrt%282%29\"$ has a perimeter of $\"4%2A36%2Asqrt%282%29\"$
\n" ); document.write( " $\"144%2Asqrt%282%29\"$ \n" ); document.write( "

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