document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150635>Question 150635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a leg of a right triangle is two times the length of the other, and the hypotenuse is 25.What is the length of the longer leg?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110572 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=length of first leg and y=length of second leg\r<BR>\n" );
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document.write( "Since the \"length of a leg of a right triangle is two times the length of the other\", this means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=2x ALIGN=MIDDLE  ALT=\"y=2x\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So in this case \"y\" is the longer leg.\r<BR>\n" );
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document.write( "So with the use of Pythagoreans theorem, we get\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=25%5E2 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=25%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2By%5E2=625 ALIGN=MIDDLE  ALT=\"x%5E2%2By%5E2=625\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square 25 to get 625\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B%282x%29%5E2=625 ALIGN=MIDDLE  ALT=\"x%5E2%2B%282x%29%5E2=625\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=2x ALIGN=MIDDLE  ALT=\"y=2x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B4x%5E2=625 ALIGN=MIDDLE  ALT=\"x%5E2%2B4x%5E2=625\"   DISABLED_style= \"max-width:90%; height:auto;\" > Square <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x ALIGN=MIDDLE  ALT=\"2x\"   DISABLED_style= \"max-width:90%; height:auto;\" > to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%5E2 ALIGN=MIDDLE  ALT=\"4x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%5E2=625 ALIGN=MIDDLE  ALT=\"5x%5E2=625\"   DISABLED_style= \"max-width:90%; height:auto;\" > Add\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2=125 ALIGN=MIDDLE  ALT=\"x%5E2=125\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 5.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=sqrt%28125%29 ALIGN=MIDDLE  ALT=\"x=sqrt%28125%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides. Note: only the positive square root is considered.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=5%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"x=5%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify the square root.\r<BR>\n" );
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document.write( "So the length of one leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=5%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"x=5%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > (which approximates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=11.18 ALIGN=MIDDLE  ALT=\"x=11.18\"   DISABLED_style= \"max-width:90%; height:auto;\" >) and the length of the longer leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=2%2A5%2Asqrt%285%29=10%2Asqrt%285%29 ALIGN=MIDDLE  ALT=\"y=2%2A5%2Asqrt%285%29=10%2Asqrt%285%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > (which approximates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=22.36 ALIGN=MIDDLE  ALT=\"y=22.36\"   DISABLED_style= \"max-width:90%; height:auto;\" >)\r<BR>\n" );
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