document.write( "Question 150631: In what proportion should 95% alcohol be mixed with 30% alcohol to make 70% alcohol? \n" ); document.write( "
Algebra.Com's Answer #110569 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Try this: \n" ); document.write( "Let x = the amount of 95% alcohol mixture required. \n" ); document.write( "Let y = the amount of 30% alcohol mixture required. \n" ); document.write( "We can write: \n" ); document.write( "0.95x+0.3y = 0.7(x+y) Expand the right side. \n" ); document.write( "o.95x+0.3y = 0.7x+0.7y Combine like-terms. \n" ); document.write( "0.25x = 0.4y \n" ); document.write( "Since we want the ratio of the amount of 95% alcohol mixture (x) to the amount of 35% alcohol mixture (y), which is x/y, we can write: \n" ); document.write( "x/y = 0.4/0.25 Simplifying this we get: \n" ); document.write( "x/y = 8/5 \n" ); document.write( "So the proportion is 8 units of 95% alcohol mixture to 5 units of 30% alcohol mixture to make 8+5 = 13 units of 70% alcohol mixture. \n" ); document.write( "Check: \n" ); document.write( "8(0.95)+5(0.3) = 13(0.7) \n" ); document.write( "7.6+1.5 = 9.1 \n" ); document.write( "9.1 = 9.1 \n" ); document.write( " |