document.write( "Question 150602: Please help me find x.\r
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document.write( "-12x^3 + 52x^2 + 54x + 12 = 0\r
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document.write( "I don't know where to go from here? Please show work so I know how to do problems like this from now on, Thanks! \r
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document.write( "My work that I think is wrong...
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document.write( "-12(x^3 - (13/3)x^2 - (27/6)x - 1) = 0\r
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document.write( "Thanks again for your help! \n" );
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Algebra.Com's Answer #110548 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Please help me find x. \n" ); document.write( "-12x^3 + 52x^2 + 54x + 12 = 0 \n" ); document.write( "x = -0.5481009, -0.3488316, or 5.2302657 \n" ); document.write( "------------- \n" ); document.write( "I used a graphing calculator to find these zeroes. \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |