document.write( "Question 150607This question is from textbook
\n" ); document.write( ": Lucy has some money invested at 18% annual interest and three times as much invested at 12%. Her total annual income from the two investments is 2200pesos. How much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #110545 by josmiceli(19441) $\"\"$ $\"About$

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Let the amount invested at 18% = $\"x\"$
\n" ); document.write( "Then the amount invested at 12% = $\"3x\"$
\n" ); document.write( " $\".18x+%2B+.12%2A3x+=+2200\"$
\n" ); document.write( " $\".18x+%2B+.36x+=+2200\"$
\n" ); document.write( " $\".54x+=+2200\"$
\n" ); document.write( " $\"x+=+4074\"$
\n" ); document.write( " $\"3x+=+12222\"$
\n" ); document.write( "4074 pesos were invested @ 18% and 12,222 pesos were
\n" ); document.write( "invested @ 12% \n" ); document.write( "

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