document.write( "Question 150585: Help!!! I have no idea how to solve these problems......\r
\n" ); document.write( "\n" ); document.write( "Solve: 2x*(x+3) = x+25\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "3x*(x+3) = 2*(5x+1)\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "(x^2-2x)(x+3) = -2x(x+1) \n" ); document.write( "

Algebra.Com's Answer #110539 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:
\n" ); document.write( "1) $\"2x%2A%28x%2B3%29+=+x%2B25\"$ First, perform the indicated distributive property on the left side.
\n" ); document.write( " $\"2x%5E2%2B6x+=+x%2B25\"$ Now combine like-terms by subtracting x from both sides.
\n" ); document.write( " $\"2x%5E2%2B5x+=+25\"$ Then subtract 25 from both sides.
\n" ); document.write( " $\"2x%5E2%2B5x-25+=+0\"$ Now you have a quadratic equation in standard form that can be solved by factoring.
\n" ); document.write( " $\"%282x-5%29%28x%2B5%29+=+0\"$ Apply the zero product rule.
\n" ); document.write( " $\"2x-5+=+0\"$ or $\"x%2B5+=+0\"$
\n" ); document.write( "If $\"2x-5+=+0\"$ then $\"2x+=+5\"$ and $\"x+=+5%2F2\"$
\n" ); document.write( "If $\"x%2B5+=+0\"$ then $\"x+=+-5\"$
\n" ); document.write( "The solutions are:
\n" ); document.write( " $\"x+=+5%2F2\"$
\n" ); document.write( " $\"x+=+-5\"$
\n" ); document.write( "2) $\"3x%2A%28x%2B3%29+=+2%2A%285x%2B1%29\"$ First, perform the indicated distributive property on both sides.
\n" ); document.write( " $\"3x%5E2%2B9x+=+10x%2B2\"$ Now combine like-terms by subtracting 10x from both sides.
\n" ); document.write( " $\"3x%5E2-x+=+2\"$ Then subtract 2 from both sides.
\n" ); document.write( " $\"3x%5E2-x-2+=+0\"$ Now you have a quadratic equation that can be solved by factoring.
\n" ); document.write( " $\"%283x%2B2%29%28x-1%29+=+0\"$ Apply the zero product rule.
\n" ); document.write( " $\"3x%2B2+=+0\"$ or $\"x-1+=+0\"$
\n" ); document.write( "If $\"3x%2B2+=+0\"$ then $\"3x+=+-2\"$ and $\"x+=+-2%2F3\"$
\n" ); document.write( "If $\"x-1+=+0\"$ then $\"x+=+1\"$
\n" ); document.write( "The solutions are:
\n" ); document.write( " $\"x+=+-2%2F3\"$
\n" ); document.write( " $\"x+=+1\"$
\n" ); document.write( "Now this should give you enough clues to do the third problem.
\n" ); document.write( "If you still have difficulty then please re-post.
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