document.write( "Question 150585: Help!!! I have no idea how to solve these problems......\r
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document.write( "Solve: 2x*(x+3) = x+25\r
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document.write( "and\r
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document.write( "3x*(x+3) = 2*(5x+1)\r
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document.write( "and\r
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document.write( "(x^2-2x)(x+3) = -2x(x+1) \n" );
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Algebra.Com's Answer #110538 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 2x(x+3) = x+25 \n" ); document.write( "2x^2+6x=x+25 \n" ); document.write( "2x^2+5x-25=0 \n" ); document.write( "2*-25=-50 what two factors of -50 when added equal 5? 10 and -5 \n" ); document.write( "2x^2+10x-5x-25=0 \n" ); document.write( "2x(x+5)-5(x+5)=0 \n" ); document.write( "(x+5)(2x-5)=0 \n" ); document.write( "x=-5, \n" ); document.write( "2x=5 x=5/2 \n" ); document.write( ". \n" ); document.write( "3x(x+3) = 2(5x+1) \n" ); document.write( "3x^2+9x=10x+2 \n" ); document.write( "3x^2-x-2=0 \n" ); document.write( "3*-2=-6 what two factors of -6 when added equal -1? 2 and -3 \n" ); document.write( "3x^2+2x-3x-2=0 \n" ); document.write( "x(3x+2)-(3x+2)=0 \n" ); document.write( "(x-1)(3x+2)=0 \n" ); document.write( "x=1 \n" ); document.write( "3x=-2 x=-2/3 \n" ); document.write( ". \n" ); document.write( "(x^2-2x)(x+3) = -2x(x+1) \n" ); document.write( "x^3+x^2-6x=-2x^2-2x \n" ); document.write( "x^3+3x^2-4x=0 \n" ); document.write( "x(x^2+3x-4)=0 \n" ); document.write( "x(x+4)(x-1)=0 \n" ); document.write( "x=0, x=-4, x=1 \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |