document.write( "Question 150587: by boat, joseph can go 72km upstream to a fishing hole in 4 hours. to go back, he needs only 3 hours. what is his rate upstream and his rate downstream? \n" ); document.write( "
Algebra.Com's Answer #110536 by edjones(8007) You can put this solution on YOUR website! rt=d \n" ); document.write( "r=d/t \n" ); document.write( "72/4=18 km/h rate upstream \n" ); document.write( "72/3=24 km/h rate downstream \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |