document.write( "Question 150562: THE WIDTH OF A RECTANGLE IS 3 FEET LESS THAN ITS LENGHTH .IF THE PERIMETER IS 22 FEET WHAT IS THE WIDTH? \n" ); document.write( "
Algebra.Com's Answer #110521 by ankor@dixie-net.com(22740)\"\" \"About 
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THE WIDTH OF A RECTANGLE IS 3 FEET LESS THAN ITS LENGHTH .IF THE PERIMETER IS 22 FEET WHAT IS THE WIDTH?
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\n" ); document.write( "Let x = the width
\n" ); document.write( "It says the length is 3 ft longer, therefore:
\n" ); document.write( "(x+3) = the length
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\n" ); document.write( "Perimeter is 2L + 2W, therefore:
\n" ); document.write( "2(x+3) + 2x = 22
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\n" ); document.write( "2x + 6 + 2x = 22
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\n" ); document.write( "2x + 2x = 22 - 6
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\n" ); document.write( "4x = 16
\n" ); document.write( "x = \"16%2F4\"
\n" ); document.write( "x = 4 ft is the width
\n" ); document.write( "and
\n" ); document.write( "4 + 3 = 7 ft is the length
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\n" ); document.write( "Check using the given perimeter
\n" ); document.write( "2(7) + 2(4) = 22 \n" ); document.write( "
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