document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22531>Question 22531</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If you boil 3 gallons of 10% salt water until ther is only 2 gallons of water. What is the percent of salt when you finish?\r<BR>\n" );
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document.write( "Next question is:<BR>\n" );
document.write( "Dilute 35 gallons of 40% acid with 7 gallons of water. What is the amount and strength of the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11052 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way to do this is to \"follow the water\".<BR>\n" );
document.write( "You started with 3 gallons that was 90%water.<BR>\n" );
document.write( "You boiled off 1 gallon that was 100%water.<BR>\n" );
document.write( "You ended up with 2 gallons that was \"x\"% water.\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "      0.9 (3) - 1(1) = (x)(2)<BR>\n" );
document.write( "       2.7    - 1    = (x)(2)<BR>\n" );
document.write( "             1.7/2  = x%<BR>\n" );
document.write( "                x = 0.850<BR>\n" );
document.write( " The 2 gallons at the end is 85% water.<BR>\n" );
document.write( " So it is a 15% salt water solution.<BR>\n" );
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document.write( "This time we will \"follow the acid\"<BR>\n" );
document.write( "You start with 35 gallons that is 40% acid.<BR>\n" );
document.write( "You add 7 gallons that is 0% acid.<BR>\n" );
document.write( "You end up with 42 gallons that is x% acid.<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "     0.40(35) + 0(7) = 42x<BR>\n" );
document.write( "       x = 14/42 = 33% acid\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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