document.write( "Question 150537: a bird species in danger of extinction has a population that is decreasing (A=A(base0)e^kt). five years ago the population was at 1400 and today only 1000 are still alive. once the population drops below 100, the situation is irreversible. When will this happen? \n" ); document.write( "
Algebra.Com's Answer #110500 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a bird species in danger of extinction has a population that is decreasing (A=A(base0)e^kt). five years ago the population was at 1400 and today only 1000 are still alive. once the population drops below 100, the situation is irreversible. When will this happen? \n" ); document.write( "---------------------------- \n" ); document.write( "A(t) = A(o) e^(kt) \n" ); document.write( "Find \"k\": \n" ); document.write( "1000 = 1400 e^(k*5) \n" ); document.write( "(5/7) = e^(5k) \n" ); document.write( "Take the ln to get: \n" ); document.write( "5k = ln (5/7) \n" ); document.write( "5k = -0.3365 \n" ); document.write( "k = -0.06729 \n" ); document.write( "--------------- \n" ); document.write( "Equation: A(t) = A(o) e^(-0.06729t) \n" ); document.write( "---------- \n" ); document.write( "When will the population be 100? \n" ); document.write( "100 = 1000 e^(-0.06729t) \n" ); document.write( "0.10 = e^(-0.06729t) \n" ); document.write( "-0.06729t = ln(0.10) \n" ); document.write( "t = 31.22 years from 5 yrs. ago \n" ); document.write( "OR \n" ); document.write( "26.22 years from NOW \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |