document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2586>Question 2586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular pond has a diameter of 2.5 meters.  The owner wants to put a concrete walkway around the pool that has uniform width.  She has enough to cover 5m(squared).  What is the maximum width her walkway can be?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1105 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1105\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If the width of the walkway is x meters, then its area is\r<BR>\n" );
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document.write( " pi(x + 2.5/2)^2 - pi (2.5/2)^2 = pi(x^2 + 2.5 x)\r<BR>\n" );
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document.write( " Solve: pi(x^2 + 2.5 x) <= 5,<BR>\n" );
document.write( " or x^2 + 2.5 x - 5/pi <= 0\r<BR>\n" );
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document.write( " use pi = 3.1416 and quadratic formula,<BR>\n" );
document.write( " two roots of  x^2 + 2.5 x - 5/pi = 0 are<BR>\n" );
document.write( "  0.525963319, -3.025963319<BR>\n" );
document.write( " when x is between these two roots, x^2 + 2.5 x - 5/pi <= 0<BR>\n" );
document.write( " but x width shouldbe > 0.\r<BR>\n" );
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document.write( " Hence,x <= 0.5259 meters... max possible value of width\r<BR>\n" );
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document.write( " Kenny<BR>\n" );
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document.write( "   </SPAN>\n" );
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