document.write( "Question 150519: A solution of 75% pesticide is to be mixed with a solution of 51% pesticide to form 48 liters of a 64% solution. How much of the 75% solution is needed? \n" ); document.write( "
Algebra.Com's Answer #110484 by mangopeeler07(462)\"\" \"About 
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A solution of 75% pesticide is to be mixed with a solution of 51% pesticide to form 48 liters of a 64% solution. How much of the 75% solution is needed?\r
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\n" ); document.write( "\n" ); document.write( "x=liters of 75%
\n" ); document.write( "48-x=liters of 51%
\n" ); document.write( "coefficient=percent\r
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\n" ); document.write( "\n" ); document.write( "75(x)+51(48-x)=64(48)\r
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\n" ); document.write( "\n" ); document.write( "Distribute
\n" ); document.write( "75x+2448-51x=3072\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms
\n" ); document.write( "24x+2448=3072\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2448 from both sides
\n" ); document.write( "24x=624\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 24
\n" ); document.write( "x=26\r
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\n" ); document.write( "\n" ); document.write( "x=liters of 75%
\n" ); document.write( "48-x=liters of 51%\r
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\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "liters of 75%=26
\n" ); document.write( "liters of 51%=22
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