document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150505>Question 150505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a grocer mixes 12kg of one grade of beans with 10kg of another grade to obtain a blend worth 540 pesos. he then makes a second blend worth 610 pesos by mixing 8kg of the first grade with 15kg of the second grade. find the price per kilogram of each grade? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #110471 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=110471\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a grocer mixes 12kg of one grade of beans with 10kg of another grade to obtain a blend worth 540 pesos. he then makes a second blend worth 610 pesos by mixing 8kg of the first grade with 15kg of the second grade. find the price per kilogram of each grade?<BR>\n" );
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document.write( "Let \"a\" be the price of 1st bean and \"b\" be the price of 2nd bean.<BR>\n" );
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document.write( "Value Equation: 12a + 10b = 540<BR>\n" );
document.write( "Value Equation:  8a + 15b = 610<BR>\n" );
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document.write( "Solve the system by substitution, elimination, or matrix to get:<BR>\n" );
document.write( "a = 20 p<BR>\n" );
document.write( "b = 30 p<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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