document.write( "Question 150497: 1986 explosion at the Chernobyl nuclear power plant in the former soviet union sent about 1000 kilograms of radioactive cesium-137 into the atmosphere. The function f(x)=1000(0.5)^x/30 describes the amount, f(x) in kilograms, of cesium-137 remaining in Chernobyl x yrs after 1986. If even 100 kilograms of cesium-137 remain in Chernobyl's atmosphere, the area is considered unsafe for humans. find f(80) and determine if Chernobyl will be safe to live in 2066. \n" ); document.write( "

Algebra.Com's Answer #110459 by josmiceli(19441) $\"\"$ $\"About$

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$\"f%28x%29+=+1000%2A%28.5%29%5E%28x%2F30%29\"$
\n" ); document.write( " $\"f%2880%29+=+1000%2A%28.5%29%5E%2880%2F30%29\"$
\n" ); document.write( " $\"f%2880%29+=+1000%2A%28.5%29%5E%282.6667%29\"$
\n" ); document.write( " $\"f%2880%29+=+1000%2A.157486\"$
\n" ); document.write( " $\"f%2880%29+=+157.486\"$ answer
\n" ); document.write( "This is unsafe since it's more than 100 kg \n" ); document.write( "

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