document.write( "Question 150467: A ball is thrown upward from a 100 foot tall building with an initial velocity of 14 feet per second. Its height s(t) in feet is given by the function s(t)= -16t^2+14t+100. Find the interval of time for which the height of the ball is greater than 103 feet.\r
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Algebra.Com's Answer #110437 by ankor@dixie-net.com(22740)\"\" \"About 
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A ball is thrown upward from a 100 foot tall building with an initial velocity of 14 feet per second. Its height s(t) in feet is given by the function s(t)= -16t^2+14t+100. Find the interval of time for which the height of the ball is greater than 103 feet.
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\n" ); document.write( "Write the equation for s = 103 ft
\n" ); document.write( "-16t^2 + 14t + 100 = 103
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\n" ); document.write( "-16t^2 + 14t + 100 - 103 = 0
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\n" ); document.write( "-16t^2 + 14t - 3 = 0
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\n" ); document.write( "Use the quadratic formula to find t:
\n" ); document.write( "\"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this problem a=-16, b=14; c=-3
\n" ); document.write( "\"t+=+%28-14+%2B-+sqrt%2814%5E2-4%2A-16%2A-3+%29%29%2F%282%2A-16%29+\"
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\n" ); document.write( "\"t+=+%28-14+%2B-+sqrt%28196+-+192%29%29%2F%28-32%29+\"
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\n" ); document.write( "\"t+=+%28-14+%2B-+sqrt%284%29%29%2F%28-32%29+\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"t+=+%28-14+%2B+2%29%2F%28-32%29\"
\n" ); document.write( "\"t+=+%28-12%29%2F%28-32%29\"
\n" ); document.write( "t = .375 sec; (passes 103 ft on the way up)
\n" ); document.write( "and
\n" ); document.write( "\"t+=+%28-14+-+2%29%2F%28-32%29\"
\n" ); document.write( "\"t+=+%28-16%29%2F%28-32%29\"
\n" ); document.write( "t = .5 sec; (passes 103 ft on the way down)
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\n" ); document.write( "So the interval of time would be .5 - .375 = .125 sec above 103 ft
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\n" ); document.write( "How about this? Does it make sense to you now?
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