document.write( "Question 150467: A ball is thrown upward from a 100 foot tall building with an initial velocity of 14 feet per second. Its height s(t) in feet is given by the function s(t)= -16t^2+14t+100. Find the interval of time for which the height of the ball is greater than 103 feet.\r
\n" );
document.write( "\n" );
document.write( "I don't even know where to start. \n" );
document.write( "
Algebra.Com's Answer #110437 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A ball is thrown upward from a 100 foot tall building with an initial velocity of 14 feet per second. Its height s(t) in feet is given by the function s(t)= -16t^2+14t+100. Find the interval of time for which the height of the ball is greater than 103 feet. \n" ); document.write( ": \n" ); document.write( "Write the equation for s = 103 ft \n" ); document.write( "-16t^2 + 14t + 100 = 103 \n" ); document.write( ": \n" ); document.write( "-16t^2 + 14t + 100 - 103 = 0 \n" ); document.write( "; \n" ); document.write( "-16t^2 + 14t - 3 = 0 \n" ); document.write( ": \n" ); document.write( "Use the quadratic formula to find t: \n" ); document.write( " \n" ); document.write( "In this problem a=-16, b=14; c=-3 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Two solutions: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t = .375 sec; (passes 103 ft on the way up) \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t = .5 sec; (passes 103 ft on the way down) \n" ); document.write( ": \n" ); document.write( "So the interval of time would be .5 - .375 = .125 sec above 103 ft \n" ); document.write( "; \n" ); document.write( "How about this? Does it make sense to you now? \n" ); document.write( " |